Пример #1
0
Файл: 2.6.go Проект: muraty/ctci
// Finds the first node of the loop
func FindCorruptNode(l ds.LinkedList) *ds.Node {
	head := l.Head()
	slowRunner := head
	fastRunner := head.Next()
	corruptNode := &ds.Node{}

	// Find the Collusion
	for {
		// There is no loop
		if slowRunner.Next() == nil || fastRunner.Next() == nil {
			return nil
		}
		// Move slow runner one point
		slowRunner = slowRunner.Next()
		// Move fast runner two points
		fastRunner = fastRunner.Next().Next()
		// Are they matched ?
		if slowRunner == fastRunner {
			fastRunner = fastRunner.Next()
			break
		}
	}
	// Find the collision point
	slowRunner = head
	for {
		if slowRunner == fastRunner {
			corruptNode = slowRunner
			break
		}
		// Move one point ahead for two of runners
		slowRunner = slowRunner.Next()
		fastRunner = fastRunner.Next()
	}
	return corruptNode
}
Пример #2
0
func initializeLoopedList() []findCorruptNodeTestPair {
	l1 := ds.LinkedList{}
	l2 := ds.LinkedList{}
	node := &ds.Node{}

	// Create a looped linked list
	// 0->1->2->3->4->5->6->3->4->5->6->3->4->5->6...
	for i := 0; i < 6; i++ {
		n := ds.Node{}
		n.SetValue(i)
		l1.Add(&n)

		if i == 5 {
			temp := l1.Head().Next().Next().Next()
			node = temp
			l1.Add(temp)
		}
	}
	// Create a non-looped linked list
	for i := 0; i < 10; i++ {
		n := ds.Node{}
		n.SetValue(i)
		l2.Add(&n)
	}
	// we can expand test cases
	var loopTests = []findCorruptNodeTestPair{
		{l1, node},
		{l2, nil}, // no loop
	}
	return loopTests
}
Пример #3
0
Файл: 2.2.go Проект: muraty/ctci
// Gives sliced linked list from kth element to last element.
// Also it assumes that, we don't know size&last element of the linkedlist.
func Slice(l datastructures.LinkedList, kth int) *datastructures.LinkedList {
	if kth <= 0 {
		return nil
	}
	current := l.Head()
	runner := current
	sliced_list := datastructures.LinkedList{}
	count := 0
	for current != nil {
		runner = current
		if count == kth {
			sliced_list.SetHead(current)
			for runner != nil {
				runner = runner.Next()
			}
			break
			sliced_list.SetTail(current)
		}
		count++
		current = current.Next()
	}
	if sliced_list.Head() != nil {
		return &sliced_list
	} else {
		return nil
	}
}
Пример #4
0
Файл: 2.1.go Проект: muraty/ctci
// Removes duplicate nodes inside the given linkedlist
func RemoveDuplicates(l *datastructures.LinkedList) {
	current := l.Head()
	for current != nil {
		runner := current
		for runner.Next() != nil {
			if runner.Next().GetValue() == current.GetValue() {
				runner.SetNext(runner.Next().Next())
			} else {
				runner = runner.Next()
			}
		}
		current = current.Next()
	}
}
Пример #5
0
Файл: 2.7.go Проект: muraty/ctci
// checks wheter given list is palindrome
func IsPalindrome(l ds.LinkedList) bool {

	head := l.Head()
	// reverse given list
	reversed_list := reverseList(l)
	reversed_head := reversed_list.Head()

	// checks items until half of the list
	for i := 0; i < l.Len()/2; i++ {
		if head.GetValue() != reversed_head.GetValue() {
			return false
		}
		head = head.Next()
		reversed_head = reversed_head.Next()
	}
	return true
}
Пример #6
0
Файл: 2.4.go Проект: muraty/ctci
// partition given list into two parts due to the given value
// and then merge them together.
func PartitionList(l datastructures.LinkedList, value int) datastructures.LinkedList {
	beforeValue := datastructures.LinkedList{}
	afterValue := datastructures.LinkedList{}

	head := l.Head()
	for head != nil {
		n := datastructures.Node{}
		n.SetValue(head.GetValue())
		if head.GetValue() < value {
			beforeValue.Add(&n)
		} else {
			afterValue.Add(&n)
		}
		head = head.Next()
	}
	beforeValue.SetTail(afterValue.Head())
	return beforeValue
}
Пример #7
0
Файл: 2.5.go Проект: muraty/ctci
// Sum up two linked list in forward order
// Input:(6 -> 1 -> 7) + (2 -> 9 -> 5).Thatis,617 + 295.
// Output: 9 -> 1 -> 2.That is, 912.
// we assume that, result integer does not exceed integer size
func SumLinkedListForward(l1 ds.LinkedList, l2 ds.LinkedList) int {
	head1 := l1.Head()
	head2 := l2.Head()
	num1 := 0
	num2 := 0
	multiplier1 := exp(10, l1.Len()-1)
	multiplier2 := exp(10, l2.Len()-1)

	// convert l1 list to int
	for head1 != nil {
		num1 += multiplier1 * head1.GetValue()
		multiplier1 = multiplier1 / 10
		head1 = head1.Next()
	}
	// convert l2 list to int
	for head2 != nil {
		num2 += multiplier2 * head2.GetValue()
		multiplier2 = multiplier2 / 10
		head2 = head2.Next()
	}
	return num1 + num2
}
Пример #8
0
Файл: 2.5.go Проект: muraty/ctci
// Sum up two linked list in reverse order
// Input:(7-> 1 -> 6) + (5 -> 9 -> 2).Thatis,617 + 295.
// Output: 2 -> 1 -> 9.That is, 912.
// we assume that, result integer does not exceed integer size
func SumLinkedListReverse(l1 ds.LinkedList, l2 ds.LinkedList) int {
	head1 := l1.Head()
	head2 := l2.Head()
	num1 := 0
	num2 := 0
	multiplier := 1

	// convert l1 list to int
	for head1 != nil {
		num1 += multiplier * head1.GetValue()
		multiplier = multiplier * 10
		head1 = head1.Next()
	}

	multiplier = 1
	// convert l2 list to int
	for head2 != nil {
		num2 += multiplier * head2.GetValue()
		multiplier = multiplier * 10
		head2 = head2.Next()
	}
	return num1 + num2
}