Пример #1
0
//	ROOT ONLY - When we know that there is a new machine pending.
//	We need to find it place in out net and send the information about it to our children.
//	We also need to create updated chart and send it to children, too.
func (s *Server) HandleNewMachine(socket net.Conn, msg string) {
	log.Println("Starting parent search")
	DataMap := sip.InterpreteData(sip.ExtractData(msg))
	fatherNode, _ := tree.FindSolution(s.Root, -1)

	log.Printf("Parent = %s\n", fatherNode.IP)

	capacity, _ := strconv.Atoi(DataMap["capacity"])
	tree.AddNewChild(fatherNode, tree.NewNode(DataMap["ip"], capacity))
	newMes := sip.FND(DataMap["ip"], fatherNode.IP)

	if fatherNode.IP == s.Address {
		log.Printf("Adding child %s %s\n", s.Address, DataMap["ip"])
		s.AddChild(DataMap["ip"])
		_, err := socket.Write([]byte(newMes.ToString()))
		log.Println(err)
	} else {
		s.AskChildren(newMes.ToString())
	}

	s.CreateChart()

	time.Sleep(1 * time.Second)

	for i := 0; i < s.ChildNumber; i++ {
		log.Printf("Sending chart to %s\n", s.Children[i])
		SendChart(s.Children[i])
	}
}
Пример #2
0
//	Creates a new server with given ip and capacity:
//	-	if root is false, it gets connected to parent,
//	-	else initializes tree node representing network structure.
func NewServer(ip string, parent string, capacity int, root bool) *Server {
	if !root {
		return &Server{ip, parent, make([]string, capacity-1), 0, nil}
	}
	return &Server{ip, parent, make([]string, capacity-1), 0, tree.NewNode(ip, capacity)}
}